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翻訳と辞書　辞書検索 [ 開発暫定版 ] スポンサード リンク Altitude (triangle) ： ウィキペディア英語版 Altitude (triangle) In geometry, an altitude of a triangle is a line segment through a vertex and perpendicular to (i.e. forming a right angle with) a line containing the base (the opposite side of the triangle). This line containing the opposite side is called the ''extended base'' of the altitude. The intersection between the extended base and the altitude is called the ''foot'' of the altitude. The length of the altitude, often simply called the altitude, is the distance between the extended base and the vertex. The process of drawing the altitude from the vertex to the foot is known as ''dropping the altitude'' of that vertex. It is a special case of orthogonal projection. Altitudes can be used to compute the area of a triangle: one half of the product of an altitude's length and its base's length equals the triangle's area. Thus the longest altitude is perpendicular to the shortest side of the triangle. The altitudes are also related to the sides of the triangle through the trigonometric functions. In an isosceles triangle (a triangle with two congruent sides), the altitude having the incongruent side as its base will have the midpoint of that side as its foot. Also the altitude having the incongruent side as its base will form the angle bisector of the vertex. It is common to mark the altitude with the letter ''h'' (as in ''height''), often subscripted with the name of the side the altitude comes from. In a right triangle, the altitude with the hypotenuse ''c'' as base divides the hypotenuse into two lengths ''p'' and ''q''. If we denote the length of the altitude by ''h''''c'', we then have the relation :$h\_c=\backslash sqrt$  (Geometric mean theorem) right For acute and right triangles the feet of the altitudes all fall on the triangle's interior or edge. In an obtuse triangle (one with an obtuse angle), the foot of the altitude to the obtuse-angled vertex falls on the opposite side, but the feet of the altitudes to the acute-angled vertices fall on the opposite extended side, exterior to the triangle. This is illustrated in the diagram to the right: in this obtuse triangle, an altitude dropped perpendicularly from the top vertex, which has an acute angle, intersects the extended horizontal side outside the triangle. ==Orthocenter== The three altitudes intersect in a single point, called the orthocenter of the triangle. The orthocenter lies inside the triangle if and only if the triangle is acute (i.e. does not have an angle greater than or equal to a right angle). If one angle is a right angle, the orthocenter coincides with the vertex of the right angle. The product of the distances from the orthocenter to a vertex and to the foot of the corresponding altitude is the same for all three altitudes.〔 This product is the squared radius of the triangle's polar circle. The orthocenter ''H'', the centroid ''G'', the circumcenter ''O'', and the center ''N'' of the nine-point circle all lie on a single line, known as the Euler line. The center of the nine-point circle lies at the midpoint between the orthocenter and the circumcenter, and the distance between the centroid and the circumcenter is half that between the centroid and the orthocenter: :$OH=2NH,$ :$2OG=GH.$ The orthocenter is closer to the incenter ''I'' than it is to the centroid, and the orthocenter is farther than the incenter is from the centroid: : :$HG\; >\; IG.$ In terms of the sides ''a, b, c'', inradius ''r'' and circumradius ''R'',〔Marie-Nicole Gras, "Distances between the circumcenter of the extouch triangle and the classical centers", ''Forum Geometricorum'' 14 (2014), 51-61. http://forumgeom.fau.edu/FG2014volume14/FG201405index.html〕 :$OH^2\; =\; R^2\; -8R^2\; \backslash cos\; A\; \backslash cos\; B\; \backslash cos\; C=9R^2-(a^2+b^2+c^2),$〔Smith, Geoff, and Leversha, Gerry, "Euler and triangle geometry", ''Mathematical Gazette'' 91, November 2007, 436–452.〕 :$HI^2\; =\; 2r^2\; -4R^2\; \backslash cos\; A\; \backslash cos\; B\; \backslash cos\; C.$ The isogonal conjugate and also the complement of the orthocenter is the circumcenter. Four points in the plane such that one of them is the orthocenter of the triangle formed by the other three are called an orthocentric system or orthocentric quadrangle. Let ''A'', ''B'', ''C'' denote the angles of the reference triangle, and let ''a'' = |''BC''|, ''b'' = |''CA''|, ''c'' = |''AB''| be the sidelengths. The orthocenter has trilinear coordinates〔Clark Kimberling's Encyclopedia of Triangle Centers http://faculty.evansville.edu/ck6/encyclopedia/ETC.html〕 $\backslash sec\; A:\backslash sec\; B:\backslash sec\; C\; =\; \backslash cos\; A-\backslash sin\; B\; \backslash sin\; C:\backslash cos\; B-\backslash sin\; C\; \backslash sin\; A:\backslash cos\; C-\backslash sin\; A\backslash sin\; B,$ and barycentric coordinates : $\backslash displaystyle\; (a^2+b^2-c^2)(a^2-b^2+c^2)\; :\; (a^2+b^2-c^2)(-a^2+b^2+c^2)\; :\; (a^2-b^2+c^2)(-a^2+b^2+c^2)$ ::$=\backslash tan\; A:\backslash tan\; B:\backslash tan\; C.$ Since barycentric coordinates are all positive for a point in a triangle's interior but at least one is negative for a point in the exterior, and two of the barycentric coordinates are zero for a vertex point, the barycentric coordinates given for the orthocenter show that the orthocenter is in an acute triangle's interior, on the right-angled vertex of a right triangle, and exterior to an obtuse triangle. Denote the vertices of a triangle as ''A'', ''B'', and ''C'' and the orthocenter as ''H'', and let ''D'', ''E'', and ''F'' denote the feet of the altitudes from ''A'', ''B'', and ''C'' respectively. Then: *The sum of the ratios on the three altitudes of the distance of the orthocenter from the base to the length of the altitude is 1:〔(Panapoi,Ronnachai, "Some properties of the orthocenter of a triangle", University of Georgia. )〕 (This property and the next one are applications of a more general property of any interior point and the three cevians through it.) :$\backslash frac\; +\; \backslash frac\; +\; \backslash frac\; =\; 1.$ *The sum of the ratios on the three altitudes of the distance of the orthocenter from the vertex to the length of the altitude is 2:〔 :$\backslash frac\; +\; \backslash frac\; +\; \backslash frac\; =\; 2.$ *The product of the lengths of the segments that the orthocenter divides an altitude into is the same for all three altitudes:〔("Orthocenter of a triangle" )〕 :$AH\; \backslash cdot\; HD\; =\; BH\; \backslash cdot\; HE\; =\; CH\; \backslash cdot\; HF.$ *If any altitude, say ''AD'', is extended to intersect the circumcircle at ''P'', so that ''AP'' is a chord of the circumcircle, then the foot ''D'' bisects segment ''HP'':〔 :$HD\; =\; DP.$ Denote the orthocenter of triangle ''ABC'' as ''H'', denote the sidelengths as ''a'', ''b'', and ''c'', and denote the circumradius of the triangle as ''R''. Then〔(Weisstein, Eric W. "Orthocenter." From MathWorld--A Wolfram Web Resource. )〕〔Altshiller-Court, Nathan, ''College Geometry'', Dover Publications, 2007 (orig. Barnes & Noble 1952), p. 102.〕 :$a^2+b^2+c^2+AH^2+BH^2+CH^2\; =\; 12R^2.$ In addition, denoting ''r'' as the radius of the triangle's incircle, ''r''''a'', ''r''''b'', and ''r''''c'' as the radii if its excircles, and ''R'' again as the radius of its circumcircle, the following relations hold regarding the distances of the orthocenter from the vertices:〔(Bell, Amy, "Hansen’s right triangle theorem, its converse and a generalization", ''Forum Geometricorum'' 6, 2006, 335–342. )〕 :$r\_a+r\_b+r\_c+r=AH+BH+CH+2R,$ :$r\_a^2+r\_b^2+r\_c^2+r^2=AH^2+BH^2+CH^2+(2R)^2.$ The directrices of all parabolas that are externally tangent to one side of a triangle and tangent to the extensions of the other sides pass through the orthocenter.〔Weisstein, Eric W. "Kiepert Parabola." From MathWorld--A Wolfram Web Resource. http://mathworld.wolfram.com/KiepertParabola.html〕 A circumconic passing through the orthocenter of a triangle is a rectangular hyperbola.〔Weisstein, Eric W. "Jerabek Hyperbola." From MathWorld--A Wolfram Web Resource. http://mathworld.wolfram.com/JerabekHyperbola.htm〕 In any acute triangle, the inscribed triangle with the smallest perimeter is the pedal triangle of the orthocenter (the triangle whose vertices are the feet of the perpendiculars from the orthocenter to the sides).〔Johnson, Roger A. ''Advanced Euclidean Geometry'', Dover Publications, 2007.〕 The sides of the pedal triangle of the orthocenter are parallel to the tangents to the circumcircle at the original triangle's vertices.〔 ==Orthic triangle== If the triangle ''ABC'' is oblique (not right-angled), the points of intersection of the altitudes with the sides of the triangle form another triangle, A'B'C', called the orthic triangle or altitude triangle. It is the pedal triangle of the orthocenter of the original triangle. Also, the incenter (that is, the center for the inscribed circle) of the orthic triangle is the orthocenter of the original triangle.〔 See also: Corollary 5.5, p. 318. 〕 The sides of the orthic triangle meet the sides of its reference triangle at three collinear points.〔Altshiller-Court, Nathan, ''College Geometry'', Dover Publications, 2007 (orig. 1952)〕〔 See also: Corollary 5.5, p. 318. 〕 The orthic triangle is closely related to the tangential triangle, constructed as follows: let ''L''''A'' be the line tangent to the circumcircle of triangle ''ABC'' at vertex ''A'', and define ''L''''B'' and ''L''''C'' analogously. Let ''A"'' = ''L''''B'' ∩ ''L''''C'', ''B"'' = ''L''''C'' ∩ ''L''''A'', ''C"'' = ''L''''C'' ∩ ''L''''A''. The tangential triangle is ''A"B"C"'', whose sides are the tangents to the reference triangle's circumcircle at its vertices; it is homothetic to the orthic triangle. The circumcenter of the tangential triangle, and the center of similitude of the orthic and tangential triangles, are on the Euler line.〔Smith, Geoff, and Leversha, Gerry, "Euler and triangle geometry", ''Mathematical Gazette'' 91, November 2007, 436–452.〕 The orthic triangle provides the solution to Fagnano's problem, posed in 1775, of finding for the minimum perimeter triangle inscribed in a given acute-angle triangle. The orthic triangle of an acute triangle gives a triangular light route.〔Bryant, V., and Bradley, H., "Triangular Light Routes," ''Mathematical Gazette'' 82, July 1998, 298-299.〕 Trilinear coordinates for the vertices of the orthic triangle are given by * A' = 0 : sec B : sec C * B' = sec A : 0 : sec C * C' = sec A : sec B : 0 Trilinear coordinates for the vertices of the tangential triangle are given by * ''A"'' = −''a'' : ''b'' : ''c'' * ''B"'' = ''a'' : −''b'' : ''c'' * ''C"'' = ''a'' : ''b'' : −''c'' For more information on the orthic triangle, see here. 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「Altitude (triangle)」の詳細全文を読む スポンサード リンク 翻訳と辞書 : 翻訳のためのインターネットリソース Copyright(C) kotoba.ne.jp 1997-2016. All Rights Reserved.